Tommy Cookers wrote:gruntguru wrote:Tommy Cookers wrote:BMEP is calculated from actual output predominantly occuring 'per active rev' ie during compression and expansion strokes (that's why the calculation of BMEP from measured power differs according to whether the engine is a 2 stroke or a 4 stroke) but the notional '3 bar exhaust' pumping loss as described by gg occurs over a half rev ie 1 stroke only (exhaust) so a 35 bar BMEP engine with 3 bar exhaust pressure reduced to 1 bar will improve the BMEP by about 1 bar (averaged over the 2 strokes) about a 3% BMEP and power improvement
If that were the case, a change to the cylinder pressure during the power stroke of say 1 bar would only change the BMEP by half a bar (which is not the case). If you check the calculation of BMEP from brake output you will find a term
"number of revolutions per power stroke" so a four stroke engine has double the BMEP of a two stroke at the same rpm and power.
well imo it seems as though it is the case ......
when I calculate the BP from your 35 bar BMEP and 5250 revolutions of a 1600 cc engine running at 10500 rpm I get 490 kW
BMEP in a 4 stroke is the steady fictitious pressure that fictitiously applies throughout the whole revolution of the engine ....
(but only to every other revolution)
and regardless of the fact that in real 4 stroke engines real pressures occur only for half revolutions
BMEP is not a steady fictitious pressure applying to half revolutions
exhaust pressure relief of 2 bar applies for half of each of the above 5250 revolutions (ie for a quarter of the total 10500 revolutions)
so cannot be directly compared to the 35 bar conventional BMEP (because this applies to the whole of the above 5250 revolutions)
exhaust pressure relief of 2 bar for half rev must be replaced by an equivalent 1 bar for the whole rev to calculate power benefit
only if we redefined BMEP as the equivalent fictitious pressure that would be need to be applied for half of the above 5250 revolutions ....
would the new BMEP (still developing the same power that the actual engine does, of course) be directly comparable with the 2 bar .....
this new BMEP would be 70 bar, and so the relief of exhaust scavenge power loss would be 2/70 ie 3% as I suggested before
it would be interesting to see a textbook expression for power loss on the exhaust stroke due to exhaust pressure
I bar average pressure during the exhaust stroke = 1 bar loss of BMEP
Work per cycle is the area enclosed by the loops in the pv diagram. Clockwise loops are positive work and anti-clockwise loops are negative (pumping) work.
The high pressure loop is formed by the compression stroke (-ve work created by positive pressure while reducing volume) and the power stroke (+ve work created by positive pressure while increasing volume). The high pressure loop is the only part analysed in the classical Otto cycle analysis.
The low pressure loop is formed by the exhaust stroke (-ve work created by positive pressure while reducing volume) and the intake stroke (-ve work created by negative pressure while increasing volume).
BMEP is work/cycle divided by displacement. Note that displacement is Vmax - Vmin on the pv diagram.
So if you increase the exhaust pressure by 1 bar, the pumping work will increase by 1bar x displacement and the BMEP will reduce by 1 bar x displacement/displacement = 1 bar.
Wikipedia link showing formulas for BMEP for 2 stroke and 4 stroke.
https://en.wikipedia.org/wiki/Mean_effective_pressure