Pushing it up against what?BassVirolla wrote: ↑11 Jan 2022, 21:55
If I understood rightly the ScalexF1's post, the damper will be pushing the knuckle up, so a pull rod layout over low frequency bumps, will be an "inverted push rod" while travelling over high frequency bumps, because the damper will be pushing the wheel up indeed.
Nevertheless, this can be accomplished with push or pull rod indistinctly, I think.
The spring force is what keeps it there, the damper is reacting against the spring force in rebound...