pompelmo wrote:ok, i want to know in anybody has the formula of aerodynamic drag energy (Wa)..
W(s)=? ....s=path
I have no idea solvig the equaison Wa=integral(F ds)...F=drag...
thanks..
Try to use "aerodynamic power": P=F*V where F is the aerodynamic drag and V is the car's speed. As the aerodynamic drag is given by F=0.5*Cx*rho*A*V^2 where A is the frontal area of the car, the aerodynamic power is proportional to V^3.
As soon as you have P=0.5*Cx*rho*A*V^3, maybe you have the equation of V in function of the time (something like V=a.t+Vo). So you just have to do integral(0.5*Cx*rho*A*V^3)dt to find out the energy "wasted" by the car.
Do the others agree with me? I'm not sure of that, send me a feedback, please.
