I will refine my statement to exclude the source of X that is causing the movement of the slave cylinders attached to the rockers in the mercury system.jav wrote:I understand what your trying to say but it seems your not getting an important point. Force or pressure are NOT being "created" by the mercury column, The intertia acting on the mercury are creating "flow".
You are not reading my sentence 100%. I gave two examples. I don't know why you bring bump stop into the equation? How do you reach the bump stops? (explain).nsmikle,
lifting the wheels off the ground will draw the dampers to their bump stops correct since there is no load on the suspension. So the inertia valve cannot.
Right so you contend that it will move due to the cars inclination.
Lets assume that the mercury is entrained on either end of the containing vessel by a piston.
Remember that this is a closed system transfering applied forces at the wheels to the mercury column to create a flow to move fluid to resist suspension travel at a present load.
With no load at an angle of say 45 degrees you contend the mercury column will move due to its own weight and pump the suspension fluid to lower the front wishbones.
How can it do this if the front suspension is already at its bump stops and has no where to go.....?
a) Yes- it's a response. But so is the compression of the spring, compression of a damper, movement of a push/pull rod. All are responses and all are legal.hardingfv32 wrote:I will refine my statement to exclude the source of X that is causing the movement of the slave cylinders attached to the rockers in the mercury system.jav wrote:I understand what your trying to say but it seems your not getting an important point. Force or pressure are NOT being "created" by the mercury column, The intertia acting on the mercury are creating "flow".
ONE purpose of the system to maintain ride height under braking, True or False? This is accomplished thru the use of slave cylinders on the rockers or more broadly stated, the suspension.
MY CHALLENGE to the legality of the system focuses on the requirement of the system that "response results only from changes in load applied to the wheels" 10.1.2
HERE IS THE TEST THAT PROVES MY POINT:
a) Is movement of the slave cylinders attached to the rockers a response, Yes or No?
b) During braking can we label the many 'loads' that are effecting the wheels in total as 'L' for this test?
When the mercury system is functioning we see a value of total loads L at the wheels when the car when the car is braking.
When the mercury system is DISABLED BUT STILL IN PLACE on the car we see a value of total loads L at the wheels when the car is braking.
Is there any difference is L whether the system is in use or not? NO
Thus, this system is clearly NOT responding only to changes in loads applied to the wheels as required by 10.1.2.
Your response?
Brian
disagree, it may not be proportional to wheel load but it is certainly dependant.n smikle wrote:You are not reading my sentence 100%. I gave two examples. I don't know why you bring bump stop into the equation? How do you reach the bump stops? (explain).nsmikle,
lifting the wheels off the ground will draw the dampers to their bump stops correct since there is no load on the suspension. So the inertia valve cannot.
Right so you contend that it will move due to the cars inclination.
Lets assume that the mercury is entrained on either end of the containing vessel by a piston.
Remember that this is a closed system transfering applied forces at the wheels to the mercury column to create a flow to move fluid to resist suspension travel at a present load.
With no load at an angle of say 45 degrees you contend the mercury column will move due to its own weight and pump the suspension fluid to lower the front wishbones.
How can it do this if the front suspension is already at its bump stops and has no where to go.....?
These cars are designed to take 5 G loads under breaking, I don't think driving the car down a 5 degree slope at 10 miles per hour is going to hit the bump stops. According to my calculations a mercury water system with 65mm pistons will push down 10kg, times the motion ratio, on each front corner of the wheel while on said 5 degree slope. All it means is that no matter what position the suspension is in this unbalanced force will exist. Agree?
and by the way.. All I did was show that the suspension response is independent of wheel load. Agree?
Yes, what you state is maybe true in a very broad sense. I would say that the above general statement fulfills: "response results only from changes in load applied to the wheels" 10.1.2.jav wrote: The point being that a suspension system alters how those loads are carried between the 4 corners. Even though the total load may not change, the amount of load carried by any given corner will vary by design and system used. If it didn't, you wouldn't see the front compress under braking or the rear conpress under acceleration. That compression is a "response" to total "L" be redistributed.
This is THE FLAW in your defense of the mercury system. IF this statement is true then:Raptor22 wrote:disagree, it may not be proportional to wheel load but it is certainly dependant.
Brian-hardingfv32 wrote:Yes, what you state is maybe true in a very broad sense. I would say that the above general statement fulfills: "response results only from changes in load applied to the wheels" 10.1.2.jav wrote: The point being that a suspension system alters how those loads are carried between the 4 corners. Even though the total load may not change, the amount of load carried by any given corner will vary by design and system used. If it didn't, you wouldn't see the front compress under braking or the rear conpress under acceleration. That compression is a "response" to total "L" be redistributed.
Your above statement does nothing to validate the legitimacy of the mercury system under 10.1.2 though. Just because you have movements similar to those in your above statement, does not make the mercury system legal. Is must still meet the requirements of 10.1.2.
Keep your focus very narrow as I have on 10.1.2. Challenge the very sentences that I have used.
Brian
Try this:Raptor22 wrote:disagree, it may not be proportional to wheel load but it is certainly dependant.n smikle wrote:You are not reading my sentence 100%. I gave two examples. I don't know why you bring bump stop into the equation? How do you reach the bump stops? (explain).nsmikle,
lifting the wheels off the ground will draw the dampers to their bump stops correct since there is no load on the suspension. So the inertia valve cannot.
Right so you contend that it will move due to the cars inclination.
Lets assume that the mercury is entrained on either end of the containing vessel by a piston.
Remember that this is a closed system transfering applied forces at the wheels to the mercury column to create a flow to move fluid to resist suspension travel at a present load.
With no load at an angle of say 45 degrees you contend the mercury column will move due to its own weight and pump the suspension fluid to lower the front wishbones.
How can it do this if the front suspension is already at its bump stops and has no where to go.....?
These cars are designed to take 5 G loads under breaking, I don't think driving the car down a 5 degree slope at 10 miles per hour is going to hit the bump stops. According to my calculations a mercury water system with 65mm pistons will push down 10kg, times the motion ratio, on each front corner of the wheel while on said 5 degree slope. All it means is that no matter what position the suspension is in this unbalanced force will exist. Agree?
and by the way.. All I did was show that the suspension response is independent of wheel load. Agree?
Not that simple. It's not a matter of semantics. A response means you poke something with a stick and it twitches a certain way. What we are arguing is if the Mercury inertial valve is a second stick.dren wrote:10.1.2 The suspension system must be so arranged that its response results only from changes in
load applied to the wheels
The mercury moves forward from the same load that causes the nose to dive. The mercury suspension is a response to the same change in load that causes the dive that it opposes. It fits within 10.1.2
The fun in this exercise is to see if it fits under the existing rule set. The system does not actually have to be under development or being reviewed by the FIA. It is just an interesting technical puzzle.jav wrote:All I've ever espoused is that while I feel a system of this type "could" be legal, I have made logical arguements to support that premise while accepting that Charlie may determine otherwiser. I don't see anything in your arguements that clearly or even marginally makes more sense than the opposing view. I guess we'll have to agree to disagree.
hardingfv32 wrote:This is THE FLAW in your defense of the mercury system. IF this statement is true then:Raptor22 wrote:disagree, it may not be proportional to wheel load but it is certainly dependant.
Why is the total of ALL loads seen by the wheels NO different whether the mercury system is functioning or not functioning (but still on chassis)? CLEARLY the mercury system's actions/responses are NOT related to the loads found at the wheels.
That is my challenge to your position.
Brian