mep wrote:As I flew over the text I recognised that you didn't take
weight balance into account.
The F1 car is only rear wheel driven so lets say 40%
of the force on the driven wheels are lost for acceleration.
Some of it can be recovered by the weight shifting caused by
the acceleration.
Thanks, mep, for reading. You're right, I did not take in account weight transfer in a dragster. I did not think about it, point taken. Friction factors for F1 cars must be corrected and therefore, must be higher that the figures you get if you simply calculate net acceleration. Something like this, for an F1 car that goes from 0 to 100 kph in 2 seconds with a weight distribution of 40% front and 60% rear:
Acceleration = 100km/h / 2sec = 13.8 m/s2 = 1.4 G
Friction coefficient = 1.4 / 60% = 2.3
Which is much larger than the value of 1 assumed by Djones teacher and consistent with the value of 2.2 I got for a dragster.
Anyway, I believe there is no need (in a dragster) to take in account weight balance. The weight transfer must be almost 100%, as this photo shows, so probably the friction coefficient for a drag tire is around 2.2, as I mentioned:
Now that I think about it, weight transfer on a modern dragster is "negative" or "over 100%", meaning that the front tires does not weigh at all, but the "skids" in the back of the dragster do.
The "ideal" run should keep the car as much as possible in a state of balance as the previous photo shows: any weight transferred to those rear skids means less final acceleration.
Besides, you probably need some weight on the front tyres to be able to steer a little your dragster: the larger the steering wheel correction you need to stay on track, the less you can accelerate, if you wish to find the "grip" on the front tyres needed to steer.