100kg/hr x 45,000kJ/kg / 3600s/hr x 0.4 x 1.33hp/kWxpensive wrote:Pardon my ignorance, but kindly present those calculations again, which "we" have covered?Moose wrote: ...
As we covered earlier in the thread, 40% efficiency could be as high as 770 Hp, depending on the exact energy content of the fuel.
That is not what he is suggesting at all.ringo wrote:interesting read. It is suggesting that kers harvesting from the engine during acceleration is somewhat a kind of traction control.
See:xpensive wrote:Pardon my ignorance, but kindly present those calculations again, which "we" have covered?Moose wrote: ...
As we covered earlier in the thread, 40% efficiency could be as high as 770 Hp, depending on the exact energy content of the fuel.
I know what he is saying. But sending the extra power to the batteries by loading the engine with KERS is somewhat of a torque limiter. It's not active traction control, but it still can limit wheel spin.wuzak wrote:That is not what he is suggesting at all.ringo wrote:interesting read. It is suggesting that kers harvesting from the engine during acceleration is somewhat a kind of traction control.
He is saying that in order to harvest the maximum allowed 2MJ per lap that they will burn fuel to drive the MGUK. In other words, if the driver demands 250kW with his right foot, the computer gets the ICE to make 300kW while harvesting 50kW from the MGUK. (Numbers used as example only.)
The use of the MGUK to act as traction control is illegal.
Burning fuel to harvest is one tactic to charge the ES. The other is "lift and coast". This is something that many fans thought was fuel saving. Evidently the time lost in the lift-coast regime is less than that gained by having the full allowed 2MJ from harvesting.
I took from the article that the energy strategy depends a lot on the circuit. An example he used was Suzuka - where a lot of the ES is used on the straight at the beginning of the lap, then scrambling for energy for the rest.
I didn't quite get what he was talking about "the cliff".
http://www.f1technical.net/forum/viewto ... 46#p549846Moose wrote: ...
It's unlikely that 770 horse power is the right answer, but still, you can not assert things like "660 horse power is 40% efficiency" (that would be based of Reid Harrison's estimate, which is the lowest I can find). Instead, 40% efficiency lies somewhere between 660 horse power and 770 horse power. Somewhere around 700 horse power is likely.
Congratulations on duplicating the calculation I did with yet another different input number, and coming up with another output in the same range as considered above.xpensive wrote:http://www.f1technical.net/forum/viewto ... 46#p549846
You're making things too complicated for yourself, if gasoline holds 44.2 MWs/kg, 0.0278 kg/s means 0.0278 * 44.2 = 1.23 MW input.
40% efficiency gives 1.23 * 0.4 = 0.489 MW, or 492 kW, which means 669 metric Hp.
So what is it now, still 770 Hp, or is "somewhere between 500 and 900 Hp" perhaps the safest bet?
Bump. Just wanted an answer. Did you simply mean it has unequal length primaries?Pierce89 wrote:The log is a variable length exhaust? Care to elaborate?WilliamsF1 wrote:The Merc engine has a log style exhaust, which in turn is a variable length exhaust
Does Merc have a variable length tuned intake system to compensate/compliment the exhaust system
a couple of systems come to mind
http://www.njstangers.org/members/norm- ... 3-vris.jpg
http://i181.photobucket.com/albums/x79/ ... MG1132.jpg