No I didn't used torque and wheel radius method that u mentioned. (U mean this : P=TorquexRpm ,Torque=Fxr)Mudflap wrote: ↑05 Apr 2017, 22:20I presume you estimated a wheel diameter, calculated wheel torque required to overcome the total resistance and then calculated power from torque using the same engine speed for all cars ? Unfortunately in this case the results are very sensitive to gearbox ratios.. hard to distinguish between a difference in power and a difference in gearing.amho wrote: ↑05 Apr 2017, 21:13Hi, there is some claims in this forum that Honda is 150 hp down to Mercedes that made me curious to do some estimation to assess the situation so I did my calculations based on these parameters:
-front area: 1.442 m^2 based on measuring-scaling Ferrari photo(pic link in follow)
-Air density: 1.225 kg/m^2
-car weight: 628 kg
-rolling coefficient: 0.015 (in the worst case)
-After a quick search on the net I found that Cd changes from 0.7 to 1.2 based on aero. configuartion for these F1 cars so I considered three different drag coefficient: 0.7, 1, 1.2 to compare different scenarios.
-I assumed qualifying speed traps(Alonso for Honda: 316.6 km/h , Stroll as fastest Mercedes: 328.6 km/h, Bottas the slowest Mercedes: 321.1 km/h)
and final result:
-If we consider Cd equal to 0.7 then Honda power deficit to fastest Mercedes is 65hp and the slowest Mercedes only 24 hp!
-If we consider Cd equal to 1 then Honda power deficit to fastest Mercedes is 95hp and the slowest Mercedes 35 hp!
-If we consider Cd equal to 1.2 then Honda power deficit to fastest Mercedes is 114hp and the slowest Mercedes 41 hp!
correct me if u see any mistakes.
https://drive.google.com/open?id=0B4O-M ... k41RmNlUE0
https://drive.google.com/open?id=0B4O-M ... DhXQ3VfOG8
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I used the following equations:
P=FxV
Where
V as car speed
F=drag force+rolling resistance force
Drag force=0.5xRhoxCdxAxV^2
Rolling resistance=(rollig coefficoint)xMxG